[InlineCost] Find more free binary operations
Currently, inline cost model considers a binary operator as free only if both its operands are constants. Some simple cases are missing such as a + 0, a - a, etc. This patch modifies visitBinaryOperator() to call SimplifyBinOp() without going through simplifyInstruction() to get rid of the constant restriction. Thus, visitAnd() and visitOr() are not needed. Differential Revision: https://reviews.llvm.org/D41494 llvm-svn: 321366
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