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Devang Patel authored
If known DebugLocs do not match then two DBG_VALUE machine instructions are not identical. For example, DBG_VALUE 3.310000e+02, 0, !"ds"; dbg:sse.stepfft.c:138:18 @[ sse.stepfft.c:32:10 ] DBG_VALUE 3.310000e+02, 0, !"ds"; dbg:sse.stepfft.c:138:18 @[ sse.stepfft.c:31:10 ] These two MIs represent identical value, 3.31..., for one variable, ds, but they are not identical because the represent two separate instances of inlined variable "ds". llvm-svn: 134620
bf8cc60d
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