[Analyzer] Fix assumptions about const field with member-initializer
Essentially, having a default member initializer for a constant member does not necessarily imply the member will have the given default value. Remove part of a2e05363 ([analyzer] Treat more const variables and fields as known contants., 2018-05-04). Fix #47878 Reviewed By: r.stahl, steakhal Differential Revision: https://reviews.llvm.org/D124621
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