[SLP] remove dead code in reduction matching; NFC
To get into this block we had: !A || B || C and we checked C in the first 'if' clause leaving !A || B. But the 2nd 'if' is checking: A && !B --> !(!A || B)
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To get into this block we had: !A || B || C and we checked C in the first 'if' clause leaving !A || B. But the 2nd 'if' is checking: A && !B --> !(!A || B)